It shows a simple graph of an with and without bypass filter circuit voltage difference, I wanted to recreate this picture.
I have coded the noise and created the graph of the noisy signal:
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import numpy as np import matplotlib.pyplot as plt %matplotlib inline v_in = np.random.uniform(-0.005,0.005,150)+5 v_out = 1/(1+1*0.1E-6*s)*v_in #this line is wrong, no such thing as '*s' plt.plot(v_in) plt.plot(v_out) plt.axis([0, 150, 4.95, 5.05]) plt.title('Bypass capacitor') plt.ylabel('Volts') plt.xticks(v_in, " ") plt.show()
Now the difficult part is that I want to solve this by having the parallel capacitor be represented as an RC low pass circuit with R = 1, and the corosponding transfer function of
I am confused with what to do with the 's', I think a laplace transform of the input? please help, i can work with impedances and AC-frequency, but a complex signal is new. a bit of theory behind the laplace 's' variable followed by the simple demo partialy set up would be very much appriciated!